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PYTHAGOREAN THEOREM EXPLORATION 2 (CUT-OUTS)

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Pythagorean Theorem Exploration 2 Cutouts
Here is the second part of the previous post (Pythagorean Exploration 1 cut-outs). The first one uses the other two sides (a and b) of the right triangle to form the sides of the square pattern. This time, the hypotenuse (c) will be used for the sides of the square. You may use the discussion in Pythagorean Exploration 2 as a guide.

You may download this template for personal use and for your math class activity. The length of the sides on the second page measures 6.5 inches. This is also the measure of the length of the hypotenuse of the right triangle on the first page.


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PYTHAGOREAN THEOREM (Exploration 2)

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The Pythagorean Theorem
Here is another proof for the Pythagorean Theorem. You can see the first part here.
Start with a cutout of a right triangle.
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Cut three more cutouts.
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Let us name the sides of the right triangle with c as the hypotenuse.
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Now, let us form a square using the four (4) triangles. This time, use the hypotenuse as the sides of the square.
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Let us take a look at the different parts of the square we formed. If we separate the whole square, we can get its area in terms of c.
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The middle part is also a square with sides equal to the difference of sides b and a. The area can be obtained as
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On the other hand, the area of the four triangles outlining the sides of the whole square is as follows.
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Combining their areas, we obtain
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Thus, c^2 = a^2 + b^2.

Your questions, comments and suggestions are welcome here. Kindly write them in the comment box below.

PYTHAGOREAN THEOREM (Exploration 1)

Trigonometry, mathematics, right triangles, geometry, math proof, math explorations, math tricks, math trivia
The Pythagoras' Theorem
The Pythagorean theorem is also known as the Pythagoras' theorem. It is named after a famous Greek mathematician, Pythagoras, who is credited for its proof.

The theorem states that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the remaining sides. That is c^2 = a^2 + b^2, where c is the hypotenuse, a and b are the lengths of the remaining sides.

Here is one of the theorem. Take note that the theorem only applies to right triangles.
Start with a cutout of any right triangle.
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 Let us name the shortest side as a, the longer side as b and the hypotenuse as c.
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Let us make three (3) more of the right triangle.
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Our next step is to form a square out of the four (4) triangles, making sure that the combined length of a and b will be the length of the side of the square that we are forming.
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Let us take a look at the different parts of the square we formed. If we separate the whole square, we can get its area in terms of a and b.
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The middle part is also a square with sides equal to the hypotenuse of the right triangle. The area can also be obtained.
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The area of the four right triangles outlining the sides of the whole square is as follows
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We take note that the area of the whole square is equal to the area of the small square in the middle added to the area of the four right triangles. That is
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Thus, c^2 = a^2 + b^2.

Hope this will help you understand the derivation of the Pythagoras' Theorem.

Your comments and suggestions are welcome here. You may write them in the comment box below. Thank you!

EXTERIOR ANGLE THEOREM (Part 2: Proof)


Here is the two-column proof for the EXTERIOR ANGLE THEOREM. You may download and print it for your perusal.


Your comments and suggestions are welcome here. You may write them in the comment box below. 

THE SUM OF THE ANGLES OF A TRIANGLE (Part 1: Exploration)

mathematics,geometry,angles,triangles,IGCSE

Everybody knows that the sum of the measures of the angles of any triangle is 180 degrees. If I may ask each one of you why, one of the reasons that I may probably hear is that "Our math teacher told us!"  - which should not be the case. You should know how to show that the sum of the angles of any triangle is really 180 degrees. Where do 180 degrees come from? Why 180 degrees? Why not 360 degrees?

The purpose of this post is to show you how to prove that the sum of the angles of any triangle is really 180 degrees. This is the first method, which is the elementary way - the easiest way, to prove it. The other methods will also be posted here. 

PROVE: The sum of the measures of the angles of any triangle is 180 degrees.

PRE-REQUISITE
: The sum of the measures of the angles that form a straight line is 180 degrees.

MATERIALS NEEDED: colored papers or cardboards, pair of scissors, ruler, marker

PROCEDURES:
1. Cut three different types of triangles, classified according to angles. Use the colored papers or cardboards for the triangles. One should be a right triangle, another should be an acute triangle and the last should be an obtuse triangle.
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2. For us to easily identify the angles of the triangles later, highlight the edges of each triangle using a black (or any dark colored) marker.
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3. Using a pair of scissors or cutter, cut the sector/region of the angles of each triangle.
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4. For each of the triangles, arrange the regions of the angles in such a way that they are adjacent to each other. Notice that in this case, the lower part of the angles form a straight line.

5. In each of the figures formed, the angles formed a straight line at the bottom part. Recall that the sum of the angles that form a straight line is 180 degrees.

CONCLUSION: The sum of the measures of the angles of any triangle is 180 degrees.

For educators and parents, I have made a worksheet for this activity for your class/children. You are free to download and print it. You may group your students and let each group work on a triangle or all the triangles. I hope this will be helpful.
Your comments and suggestions are welcome here. Write them in the comment box below. Thank you!

1 = 2?

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Maybe you are wondering why or how can 1 be equal to 2. Let us look at the following proof:

First, let us have two real numbers a and b wheremathematics,algebra,math proofs,trivia,tricks,puzzles,IGCSE
Using the addition property of equality, let us add b on both sides.mathematics,algebra,math proofs,trivia,tricks,puzzles,IGCSE
If we simplify both sides by combining like terms, it will become
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Now let us subtract 2a on both sides
mathematics,algebra,math proofs,equations,trivia,tricks,puzzles,IGCSECombining like terms, we will arrive at

mathematics,algebra,math proofs,equations,trivia,tricks,puzzles,IGCSE










The right side has a common factor, which is 2. Using distributive property, it can be rewritten as  
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If you notice, both sides has a common factor, which is b - a. To simplify the equation, let us divide both sides by the common factor.
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The process will arrive at
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Are you convinced? No no no...

Seems like the proof is valid but there is something wrong with it. Look over the proof once again. Can you identify which of the process is not valid?


There is nothing wrong with the given. Real numbers can be equal. There is nothing wrong also with adding b and subtracting 2a on both sides. Likewise, there is nothing wrong with combining like terms on both sides. Then, where is the mistake?

There is nothing wrong with dividing both sides by any number but in this case it becomes invalid. The reason is that b - a = 0 since a = b. Subtracting equal numbers will yield 0. Since b - a = 0, then the result will be UNDEFINED. We cannot also cancel out b - a on both sides because of that. 

Therefore, 1 is not equal to 2.  

Here is a copy of the proof in pdf form. You may download and print it for educational purposes.    You may share it to your friends. Your comments and suggestions are also welcome here. 


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